SAGAR SINGH - IIT DELHI
Last Activity: 14 Years ago
Dear student,
Write the equation of normal to parabola.
Normal at the Point (x1, y1 ):
The equation of the tangent at the point (x1, y1) is yy1 = 2a(x + x1). Since the slope of
tangent = 2a/y1 , slope of normal is -y1/ 2a . Also it passes through (x1, y1).
Hence its equation is y - y1 = y1 / 2a ( x - x1 ) . . . . . (i)
In equation (i), put - y1 / 2a = m so that y1 = -2am and x1 = y12 / 4a = am2, then the equation becomes
y = mx - 2am - am3 . . . . . (ii)
where m is a parameter. Equation (ii) is the normal at the point (am2, -2am) of the parabola.
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Sagar Singh
B.Tech, IIT Delhi
sagarsingh24.iitd@gmail.com